0=3.24x^2-0.9328x+0.051304

Solution for 0=3.24x^2-0.9328x+0.051304 equation:

0=3.24x^2-0.9328x+0.051304

We move all terms to the left:

0-(3.24x^2-0.9328x+0.051304)=0

We add all the numbers together, and all the variables

-(3.24x^2-0.9328x+0.051304)=0

We get rid of parentheses

-3.24x^2+0.9328x-0.051304=0

a = -3.24; b = 0.9328; c = -0.051304;
Δ = b2-4ac
Δ = 0.93282-4·(-3.24)·(-0.051304)
Δ = 0.205216
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0.9328)-\sqrt{0.205216}}{2*-3.24}=\frac{-0.9328-\sqrt{0.205216}}{-6.48}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0.9328)+\sqrt{0.205216}}{2*-3.24}=\frac{-0.9328+\sqrt{0.205216}}{-6.48}
$